Input and output

Inputs: two numbers a and b. Output: their sum. Choose a numeric type that can hold the allowed values and their result. Use an integer type for whole-number examples or a floating type when fractional inputs are required.

Algorithm

1. Start: Begin the solution.
2. Read a and b: Obtain both input values.
3. Calculate sum: Set sum = a + b.
4. Display sum: Show the calculated value.
5. Stop: The required result has been produced.

Pseudocode

READ a, b
sum ← a + b
OUTPUT sum

Example

Let a = 12 and b = 15. After reading the inputs, the addition gives 27. Store 27 in sum and display it. For a = −5 and b = 5, the sum is zero. No decision or repeated calculation is needed for these stated examples.

Flowchart and program

The flowchart contains Start, an input symbol, a processing rectangle for addition, an output symbol and End. The supplied program uses fixed small values so that the output can be checked easily. A program that accepts arbitrary user values must also check input conversion and ensure that the result fits the chosen type. A correct mathematical sum can still be too large for int.

Time and space complexity

The algorithm always performs one addition. Therefore its time is O(1). A fixed number of variables is used, so extra space is O(1). Adding n values would require a repeated step and would take O(n) time.

Reference table

Diagram or flowchart

C program and output

/* CodeBhavya | PPS AR25 | Learning example */
#include <stdio.h>
int main(void)
{
    int a = 12, b = 15;
    int sum = a + b;
    printf("Sum = %d\n", sum);
    return 0;
}

Sum = 27

Key points

• Read the two values, add them using a suitable numeric type, then display the result.
• The chosen C type must be able to represent the result.