ADVANCED DATA STRUCTURES PROGRAM • LEVEL 19 — FILES AND FILE ORGANIZATION
Organize Records into Hashed File Buckets
Learn how to organize records into hashed file buckets using a clear C program.
PROBLEM UNDERSTANDING
Input and expected output
Sample input
No input required
Sample output
B2: 12 7 22 17 B4: 19
COMPLETE C PROGRAM
Complete C implementation
#include <stdio.h>
int main(void)
{
int buckets[5][4]={{0}},count[5]={0},keys[]={12,7,22,19,17};for(int i=0;i<5;i++){int b=keys[i]%5;buckets[b][count[b]++]=keys[i];}for(int b=0;b<5;b++)if(count[b]){printf("B%d:",b);for(int i=0;i<count[b];i++)printf(" %d",buckets[b][i]);putchar('\n');}return 0;
}CURRENT STEP
SELECTED LINE
EXPECTED OUTPUT FOR THE SAMPLE
B2: 12 7 22 17 B4: 19
Step 0 of 0
PROGRAM EXPLANATION
Algorithm and explanation
- Read the required input values.
- Map a record key to a bucket and keep colliding records in that bucket's overflow area.
- Display the computed result.
Map a record key to a bucket and keep colliding records in that bucket's overflow area.
EFFICIENCY
Time and space complexity
Time complexity
Average O(1) access
Auxiliary space
O(records + buckets)
DEBUGGING CHECKLIST
Common mistakes
Check this
Use the correct format specifier for every variable.
Check this
Initialize variables before using their values.
Check this
Check braces, semicolons and input order carefully.
Try it yourself
Practice: Run the program with the sample input, predict its output, and then test one boundary case of your own.
