JAVA PROGRAM • LEVEL 08 — METHODS & RECURSION
Accept Variable Arguments in Java
Learn accept variable arguments in java with a complete, compiler-ready Java 17 example.
PROBLEM UNDERSTANDING
Input and expected output
No input required
20
COMPLETE JAVA 17 PROGRAM
Complete Java 17 implementation
class Main {
static int total(int... values) { int sum=0; for(int value:values)sum+=value; return sum; }
public static void main(String[] args) {
System.out.println(total(2,4,6,8));
}
}CURRENT STEP
Select Start to walk through the important lines.
SELECTED LINE
No line selected
EXPECTED OUTPUT FOR THE SAMPLE
20
PROGRAM EXPLANATION
Algorithm and explanation
- Initialize the deterministic sample values used for accept variable arguments in java.
- Apply varargs and Array in the order shown by the program.
- Print the final result and compare it with the documented sample output.
This Java 17 example demonstrates varargs and Array through a complete, executable program. The values are intentionally small so students can trace each statement, verify the output, and then modify the example safely in the online compiler.
EFFICIENCY
Time and space complexity
O(1)
O(1)
DEBUGGING CHECKLIST
Common mistakes
Keep the class name Main and the entry method signature public static void main(String[] args) when using the online compiler.
Check the loop boundary and update expression carefully to avoid skipping the final value or creating an infinite loop.
Java is case-sensitive, and every statement that requires a semicolon must end with one.