JAVA PROGRAM • LEVEL 12 — EXCEPTION HANDLING
Handle Multiple Exception Types in Java
Learn handle multiple exception types in java with a complete, compiler-ready Java 17 example.
PROBLEM UNDERSTANDING
Input and expected output
No input required
Invalid number
COMPLETE JAVA 17 PROGRAM
Complete Java 17 implementation
class Main { public static void main(String[] args){String value="abc";try{System.out.println(Integer.parseInt(value));}catch(NumberFormatException error){System.out.println("Invalid number");}catch(RuntimeException error){System.out.println("Runtime error");}} }CURRENT STEP
Select Start to walk through the important lines.
SELECTED LINE
No line selected
EXPECTED OUTPUT FOR THE SAMPLE
Invalid number
PROGRAM EXPLANATION
Algorithm and explanation
- Initialize the deterministic sample values used for handle multiple exception types in java.
- Apply Multiple catch and NumberFormatException in the order shown by the program.
- Print the final result and compare it with the documented sample output.
This Java 17 example demonstrates Multiple catch and NumberFormatException through a complete, executable program. The values are intentionally small so students can trace each statement, verify the output, and then modify the example safely in the online compiler.
EFFICIENCY
Time and space complexity
O(1)
O(1)
DEBUGGING CHECKLIST
Common mistakes
Keep the class name Main and the entry method signature public static void main(String[] args) when using the online compiler.
Use Multiple catch with compatible Java types; Java checks types and method signatures at compile time.
Java is case-sensitive, and every statement that requires a semicolon must end with one.