JAVA PROGRAM • LEVEL 17 — DATA STRUCTURES & ALGORITHMS IN JAVA
Build and Traverse a BST in Java
Learn build and traverse a bst in java with a complete, compiler-ready Java 17 example.
PROBLEM UNDERSTANDING
Input and expected output
No input required
2 3 4 5 7
COMPLETE JAVA 17 PROGRAM
Complete Java 17 implementation
class Node{int v;Node left,right;Node(int v){this.v=v;}}class Main{static Node insert(Node root,int v){if(root==null)return new Node(v);if(v<root.v)root.left=insert(root.left,v);else root.right=insert(root.right,v);return root;}static void inorder(Node root){if(root!=null){inorder(root.left);System.out.print(root.v+" ");inorder(root.right);}}public static void main(String[] args){Node root=null;for(int v:new int[]{5,3,7,2,4})root=insert(root,v);inorder(root);}}CURRENT STEP
Select Start to walk through the important lines.
SELECTED LINE
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EXPECTED OUTPUT FOR THE SAMPLE
2 3 4 5 7
PROGRAM EXPLANATION
Algorithm and explanation
- Initialize the deterministic sample values used for build and traverse a bst in java.
- Create the required object and apply BST and Inorder traversal to its state or behavior.
- Print the final result and compare it with the documented sample output.
This Java 17 example demonstrates BST and Inorder traversal through a complete, executable program. The values are intentionally small so students can trace each statement, verify the output, and then modify the example safely in the online compiler.
EFFICIENCY
Time and space complexity
O(n log n) average
O(n)
DEBUGGING CHECKLIST
Common mistakes
Keep the class name Main and the entry method signature public static void main(String[] args) when using the online compiler.
Create an object before accessing instance members; static members can be accessed through the class name.
Java is case-sensitive, and every statement that requires a semicolon must end with one.