DATA STRUCTURES PROGRAM • SINGLY LINKED LISTS
Delete the First Node of a Singly Linked List
Learn how to delete the first node of a singly linked list using a clear C program.
PROBLEM UNDERSTANDING
Input and expected output
Sample input
No input required
Sample output
20 30
COMPLETE C PROGRAM
Complete C implementation
#include <stdio.h>
#include <stdlib.h>
struct Node { int data; struct Node *next; };
struct Node *create_node(int value)
{
struct Node *node = malloc(sizeof *node);
if (node == NULL) { perror("malloc"); exit(EXIT_FAILURE); }
node->data = value;
node->next = NULL;
return node;
}
void append(struct Node **head, int value)
{
struct Node *node = create_node(value);
if (*head == NULL) { *head = node; return; }
struct Node *current = *head;
while (current->next != NULL) current = current->next;
current->next = node;
}
void print_list(const struct Node *head)
{
while (head != NULL) { printf("%d ", head->data); head = head->next; }
putchar('\n');
}
void free_list(struct Node *head)
{
while (head != NULL) { struct Node *next = head->next; free(head); head = next; }
}
int main(void)
{
struct Node *head = NULL;
append(&head, 10); append(&head, 20); append(&head, 30);
if (head != NULL) { struct Node *removed = head; head = head->next; free(removed); }
print_list(head);
free_list(head);
return 0;
}CURRENT STEP
SELECTED LINE
EXPECTED OUTPUT FOR THE SAMPLE
20 30
Step 0 of 0
PROGRAM EXPLANATION
Algorithm and explanation
- Read the required input values.
- Save the current head, advance head to the second node and release the removed node.
- Display the computed result.
Save the current head, advance head to the second node and release the removed node.
EFFICIENCY
Time and space complexity
Time complexity
O(1)
Auxiliary space
O(n)
DEBUGGING CHECKLIST
Common mistakes
Check this
Use the correct format specifier for every variable.
Check this
Initialize variables before using their values.
Check this
Check braces, semicolons and input order carefully.
Try it yourself
Practice: Run the program with the sample input, predict its output, and then test one boundary case of your own.
