DATA STRUCTURES PROGRAM • SINGLY LINKED LISTS
Count Nodes in a Singly Linked List
Learn how to count nodes in a singly linked list using a clear C program.
PROBLEM UNDERSTANDING
Input and expected output
Sample input
No input required
Sample output
Nodes = 4
COMPLETE C PROGRAM
Complete C implementation
#include <stdio.h>
#include <stdlib.h>
struct Node { int data; struct Node *next; };
struct Node *create_node(int value)
{
struct Node *node = malloc(sizeof *node);
if (node == NULL) { perror("malloc"); exit(EXIT_FAILURE); }
node->data = value;
node->next = NULL;
return node;
}
void append(struct Node **head, int value)
{
struct Node *node = create_node(value);
if (*head == NULL) { *head = node; return; }
struct Node *current = *head;
while (current->next != NULL) current = current->next;
current->next = node;
}
void print_list(const struct Node *head)
{
while (head != NULL) { printf("%d ", head->data); head = head->next; }
putchar('\n');
}
void free_list(struct Node *head)
{
while (head != NULL) { struct Node *next = head->next; free(head); head = next; }
}
int main(void)
{
struct Node *head = NULL;
append(&head, 5); append(&head, 10); append(&head, 15); append(&head, 20);
size_t count = 0;
for (const struct Node *current = head; current != NULL; current = current->next) count++;
printf("Nodes = %zu\n", count);
free_list(head);
return 0;
}CURRENT STEP
SELECTED LINE
EXPECTED OUTPUT FOR THE SAMPLE
Nodes = 4
Step 0 of 0
PROGRAM EXPLANATION
Algorithm and explanation
- Read the required input values.
- Increment a counter once for every node reached before NULL.
- Display the computed result.
Increment a counter once for every node reached before NULL.
EFFICIENCY
Time and space complexity
Time complexity
O(n)
Auxiliary space
O(n)
DEBUGGING CHECKLIST
Common mistakes
Check this
Use the correct format specifier for every variable.
Check this
Initialize variables before using their values.
Check this
Check braces, semicolons and input order carefully.
Try it yourself
Practice: Run the program with the sample input, predict its output, and then test one boundary case of your own.
