DATA STRUCTURES PROGRAM • TREES & BINARY SEARCH TREES

Delete a Value from a Binary Search Tree

Learn how to delete a value from a binary search tree using a clear C program.

AdvancedBinary treeNodesRecursion

PROBLEM UNDERSTANDING

Input and expected output

Sample input
No input required
Sample output
20 30 40 60 70 80

COMPLETE C PROGRAM

Complete C implementation

dsa-bst-delete.c
Open in compiler
#include <stdio.h>
#include <stdlib.h>

struct TreeNode { int data; struct TreeNode *left; struct TreeNode *right; };
struct TreeNode *new_node(int value)
{
    struct TreeNode *node = malloc(sizeof *node);
    if (node == NULL) exit(EXIT_FAILURE);
    node->data = value; node->left = NULL; node->right = NULL;
    return node;
}
struct TreeNode *sample_tree(void)
{
    struct TreeNode *root = new_node(1);
    root->left = new_node(2); root->right = new_node(3);
    root->left->left = new_node(4); root->left->right = new_node(5);
    root->right->left = new_node(6); root->right->right = new_node(7);
    return root;
}
void free_tree(struct TreeNode *root)
{
    if (root == NULL) return;
    free_tree(root->left); free_tree(root->right); free(root);
}
struct TreeNode *bst_insert(struct TreeNode *root, int value)
{
    if (root == NULL) return new_node(value);
    if (value < root->data) root->left = bst_insert(root->left, value);
    else if (value > root->data) root->right = bst_insert(root->right, value);
    return root;
}
void inorder(struct TreeNode *root)
{
    if (root == NULL) return;
    inorder(root->left); printf("%d ", root->data); inorder(root->right);
}
struct TreeNode *bst_delete(struct TreeNode *root, int key)
{
    if (root == NULL) return NULL;
    if (key < root->data) root->left = bst_delete(root->left, key);
    else if (key > root->data) root->right = bst_delete(root->right, key);
    else {
        if (root->left == NULL) { struct TreeNode *right = root->right; free(root); return right; }
        if (root->right == NULL) { struct TreeNode *left = root->left; free(root); return left; }
        struct TreeNode *successor = root->right;
        while (successor->left != NULL) successor = successor->left;
        root->data = successor->data;
        root->right = bst_delete(root->right, successor->data);
    }
    return root;
}

int main(void)
{
    int values[] = {50, 30, 70, 20, 40, 60, 80};
    struct TreeNode *root = NULL;
    for (int index = 0; index < 7; index++) root = bst_insert(root, values[index]);
    root = bst_delete(root, 50);
    inorder(root); putchar('\n');
    free_tree(root);
    return 0;
}

GUIDED CODE TOUR • NOT LIVE EXECUTION

Study the program line by line

Use the real compiler button above to run and debug with different inputs.

CURRENT STEP

Select Start to walk through the important lines.

SELECTED LINE

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EXPECTED OUTPUT FOR THE SAMPLE

20 30 40 60 70 80
0%Step 0 of 0

PROGRAM EXPLANATION

Algorithm and explanation

  1. Read the required input values.
  2. Handle leaf, one-child and two-child cases; replace a two-child node with its inorder successor.
  3. Display the computed result.

Handle leaf, one-child and two-child cases; replace a two-child node with its inorder successor.

EFFICIENCY

Time and space complexity

Time complexity

Average O(log n)

Auxiliary space

O(h)

DEBUGGING CHECKLIST

Common mistakes

Check this

Use the correct format specifier for every variable.

Check this

Initialize variables before using their values.

Check this

Check braces, semicolons and input order carefully.

Try it yourself

Practice: Run the program with the sample input, predict its output, and then test one boundary case of your own.