CASE STUDY 01 · COMMERCIAL MATHEMATICS

Intermediate Percentages + Ratio + Algebra

Tech-Fest Budget & Break-Even Planner

Protect a reserve, allocate the usable fund, evaluate successive discounts and calculate the minimum attendance required to avoid a loss.

01 · PROBLEM DEFINITION

One event requires several connected calculations

A college tech fest has a total planning budget of ₹3,00,000. Organizers first protect 12% as an emergency reserve. The remaining amount is shared among technical events, infrastructure and publicity in the ratio 5:3:2.

A vendor quotes ₹1,50,000 and offers successive discounts of 12% and 5%. Separately, the event has ₹1,20,000 fixed cost, ₹40,000 sponsorship income, ₹350 ticket price and ₹180 variable cost per attendee. The team must find the smallest whole attendance that prevents a loss and test several attendance scenarios.

Mathematical objective: distinguish percentages of different bases, preserve ratio totals, compound discounts correctly and convert a linear inequality into a practical whole-number decision.
02 · QUANTITY & UNIT MAP

Do not substitute until every quantity has a role

QuantitySymbolValueRole
Total planning budgetB₹3,00,000Base for reserve
Reserve rater12%Protected fraction
Fixed event costF₹1,20,000Independent of attendance
SponsorshipS₹40,000Revenue before tickets
Ticket/variable costp,v₹350, ₹180Per attendee
AttendancenUnknown integerDecision variable

Every monetary expression must combine rupees with rupees. A percentage is dimensionless. Attendance is a count, so a decimal solution must be rounded upward when the goal is “at least break-even.”

03 · PERCENTAGE RESERVE

Find the part, then subtract from the whole

Reserve = B × r/100
        = 3,00,000 × 12/100 = ₹36,000
Usable budget = 3,00,000 − 36,000 = ₹2,64,000

A quick reasonableness check helps: 10% is ₹30,000 and 2% is ₹6,000, so 12% must be ₹36,000. The usable amount must be less than the original budget and both parts must sum back to ₹3,00,000.

04 · PROPORTIONAL ALLOCATION

A ratio names shares, not rupee amounts

The parts 5:3:2 total 10. One ratio unit therefore equals ₹2,64,000 ÷ 10 = ₹26,400.

CategoryPartsCalculationAllocation
Technical events55 × 26,400₹1,32,000
Infrastructure33 × 26,400₹79,200
Publicity22 × 26,400₹52,800

Verification: ₹1,32,000 + ₹79,200 + ₹52,800 = ₹2,64,000. Dividing any pair of allocations recovers the intended proportion.

05 · SUCCESSIVE DISCOUNTS

Two percentage reductions use two different bases

After 12% discount = 1,50,000 × 0.88 = ₹1,32,000
After another 5%  = 1,32,000 × 0.95 = ₹1,25,400

The discounts do not add to 17%, because the second 5% is calculated on ₹1,32,000 rather than the marked price. The remaining-price factor is 0.88 × 0.95 = 0.836. Therefore the equivalent discount is (1 − 0.836) × 100 = 16.4%.

Common mistake: Adding successive percentages is valid only as an approximation for small rates, not as the exact result.
06 · BREAK-EVEN ALGEBRA

Separate fixed amount from per-attendee contribution

Revenue R(n) = 40,000 + 350n
Cost C(n)    = 1,20,000 + 180n
Require R(n) ≥ C(n)
40,000 + 350n ≥ 1,20,000 + 180n
170n ≥ 80,000
n ≥ 470.588...

The contribution per attendee is ₹350 − ₹180 = ₹170. Sponsorship reduces the uncovered fixed amount to ₹80,000. Because attendance must be a whole number, round upward: the minimum non-loss attendance is 471. At 471, profit is ₹70; at 470, loss is ₹100. Rounding to the nearest integer would produce the wrong operational decision.

07 · PROGRAMMATIC VERIFICATION

Python program using Decimal money arithmetic

programs/tech-fest-budget.py
Loading source…

The program separates reusable calculations into functions, validates impossible inputs and uses Decimal so base-10 money values do not inherit binary floating-point representation surprises.

08 · INTERACTIVE TRACING

Trace the complete decision

  1. Protect reserve.
  2. Find allocation base.
  3. Allocate budget.
  4. Compound discounts.
  5. Verify quote.
  6. Build break-even equation.
  7. Convert to whole attendance.
Current state

Press Next to begin.

09 · VERIFICATION STRATEGY

Use identities and boundary tests

Allocation conservation
Reserve plus three allocations must equal the original ₹3,00,000 exactly.
Discount factor
Final price divided by marked price must equal 0.88 × 0.95.
Break-even boundary
Test n=470 and n=471. The first must be a loss and the second non-negative.
Impossible contribution
If variable cost is at least ticket price and sponsorship does not cover fixed cost, no finite attendance can break even.
10 · PRACTICE

Check the reasoning

What is the equivalent discount for 12% followed by 5%?

Why is the answer rounded upward?

Extensions

  1. Add three ticket categories in a fixed sales ratio.
  2. Include a maximum venue capacity and test feasibility.
  3. Perform best, expected and worst attendance scenarios.
  4. Find the ticket price needed to break even at 400 attendees.
11 · INTERVIEW PREPARATION

Explain the model, not just the arithmetic

Why do successive discounts multiply?

Each step preserves a fraction of the current price. Applying 12% then 5% preserves 88% and then 95%, giving the combined factor 0.88×0.95.

What does contribution mean?

Ticket price minus variable cost is the amount each additional attendee contributes toward uncovered fixed cost and then profit.

What assumption makes the model linear?

Ticket price and variable cost per attendee are constant, while fixed cost and sponsorship do not depend on attendance.

12 · KEY TAKEAWAY

Always identify the base and the changing quantity

Percentages require the correct base, ratios require conservation, successive changes require multiplication, and break-even requires separating fixed and variable terms. Units and boundary checks connect the formula to a correct decision.